What is the inverse of f(x)=f(x)=12x3-9x2-108x+1 ?

The inverse of f(x)=f(x)=12x3-9x2-108x+1 is -(x-1)/(90)

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inverse of f(x)=f(x)=12x3-9x2-108x+1

inverse

f (x) = f (x) = 12 x 3 - 9 x 2 - 108 x + 1

- \frac{x - 1}{90}

Solution steps

y = 12 x \cdot 3 - 9 x \cdot 2 - 108 x + 1

Replace

x

with

y

x = 12 y \cdot 3 - 9 y \cdot 2 - 108 y + 1

Solve for

y, x = 12 y 3 - 9 y 2 - 108 y + 1

- \frac{x - 1}{90}

f (x) = \frac{9 x + 8}{8 x - 3}

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

f (x) = 2^{(x)} + 5

f (x) = \frac{8}{x - 4}

lo g_{10} (x + 2) + lo g_{10} (5)

What is the inverse of f(x)=f(x)=12x3-9x2-108x+1 ?
The inverse of f(x)=f(x)=12x3-9x2-108x+1 is -(x-1)/(90)