What is the inverse of f(x)=(9x+8)/(8x-3) ?

The inverse of f(x)=(9x+8)/(8x-3) is (8+3x)/(8x-9)

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inverse of f(x)=(9x+8)/(8x-3)

inverse

f (x) = \frac{9 x + 8}{8 x - 3}

\frac{8 + 3 x}{8 x - 9}

Solution steps

y = \frac{9 x + 8}{8 x - 3}

Replace

x

with

y

x = \frac{9 y + 8}{8 y - 3}

Solve for

y, x = \frac{9 y + 8}{8 y - 3}

\frac{8 + 3 x}{8 x - 9}

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

f (x) = 2^{(x)} + 5

f (x) = \frac{8}{x - 4}

lo g_{10} (x + 2) + lo g_{10} (5)

f (x) = \frac{1}{3} lo g_{2} (x)

What is the inverse of f(x)=(9x+8)/(8x-3) ?
The inverse of f(x)=(9x+8)/(8x-3) is (8+3x)/(8x-9)