What is the inverse of f(x)=1+e^{1+sqrt(1-x)} ?

The inverse of f(x)=1+e^{1+sqrt(1-x)} is -ln^2(x-1)+2ln(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=1+e^{1+sqrt(1-x)}

inverse

f (x) = 1 + e^{1 + 1 - x}

- ln^{2} (x - 1) + 2 ln (x - 1)

Solution steps

y = 1 + e^{1 + 1 - x}

Replace

x

with

y

x = 1 + e^{1 + 1 - y}

Solve for

y, x = 1 + e^{1 + 1 - y}

- ln^{2} (x - 1) + 2 ln (x - 1)

7 m

f (x) = \frac{z ^{- 1}}{2 \cdot ( 1 - z ^{- 1} )}

f (x) = \frac{x ^{2} + 2}{x - 1}

f (y) = arcsin (x)

f (x) = \frac{( 3 x - 7 )}{5}

What is the inverse of f(x)=1+e^{1+sqrt(1-x)} ?
The inverse of f(x)=1+e^{1+sqrt(1-x)} is -ln^2(x-1)+2ln(x-1)