What is the inverse of f(x)=(z^{-1})/(2*(1-z^{-1))} ?

The inverse of f(x)=(z^{-1})/(2*(1-z^{-1))} is 1/(z*2)+1

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inverse of f(x)=(z^{-1})/(2*(1-z^{-1))}

inverse

f (x) = \frac{z ^{- 1}}{2 \cdot ( 1 - z ^{- 1} )}

\frac{1}{z \cdot 2} + 1

Solution steps

x = \frac{z ^{- 1}}{2 ( 1 - z ^{- 1} )}

Replace

z

with

x

z = \frac{x ^{- 1}}{2 ( 1 - x ^{- 1} )}

Solve for

x, z = \frac{x ^{- 1}}{2 \cdot ( 1 - x ^{- 1} )}

\frac{1}{z \cdot 2} + 1

f (x) = \frac{x ^{2} + 2}{x - 1}

f (y) = arcsin (x)

f (x) = \frac{( 3 x - 7 )}{5}

f (x) = lo g_{10} (4^{x + 2})

f (x) = 1 - (x - 1)^{2}

What is the inverse of f(x)=(z^{-1})/(2*(1-z^{-1))} ?
The inverse of f(x)=(z^{-1})/(2*(1-z^{-1))} is 1/(z*2)+1