What is the inverse of 3(x-4)^2+5 ?

The inverse of 3(x-4)^2+5 is sqrt((x-5)/3)+4,-sqrt((x-5)/3)+4

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inverse of 3(x-4)^2+5

inverse

3 (x - 4)^{2} + 5

\frac{x - 5}{3} + 4, - \frac{x - 5}{3} + 4

Solution steps

y = 3 (x - 4)^{2} + 5

Replace

x

with

y

x = 3 (y - 4)^{2} + 5

Solve for

y, x = 3 (y - 4)^{2} + 5

\frac{x - 5}{3} + 4, - \frac{x - 5}{3} + 4

1 - 2^{x}

f (x) = 1 + \frac{4 x}{x + 3}

- 0.25 x^{2} + 15 x - 200

2 x^{2} - \frac{1}{3} x - \frac{19}{14}

\frac{s + 2}{s ^{2} + 25}

What is the inverse of 3(x-4)^2+5 ?
The inverse of 3(x-4)^2+5 is sqrt((x-5)/3)+4,-sqrt((x-5)/3)+4