What is the inverse of f(x)=8x^2-27,[0,infinity ] ?

The inverse of f(x)=8x^2-27,[0,infinity ] is (sqrt(2)sqrt(x+27))/4 ,-(sqrt(2)sqrt(x+27))/4

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inverse of f(x)=8x^2-27,[0,infinity ]

inverse

f (x) = 8 x^{2} - 27, [0, \infty]

\frac{2 x + 27}{4}, - \frac{2 x + 27}{4}

Solution steps

y = 8 x^{2} - 27

Replace

x

with

y

x = 8 y^{2} - 27

Solve for

y, x = 8 y^{2} - 27

\frac{2 x + 27}{4}, - \frac{2 x + 27}{4}

f (x) = \frac{1}{3 x}, x \neq = 0

f (x) = x^{2} + 10 x, x \geq - 5

f (x) = \frac{ln ( \frac{x}{3 - x} )}{4}

f (x) = 3 x^{2} + x

lo g_{10} (0.016576)

What is the inverse of f(x)=8x^2-27,[0,infinity ] ?
The inverse of f(x)=8x^2-27,[0,infinity ] is (sqrt(2)sqrt(x+27))/4 ,-(sqrt(2)sqrt(x+27))/4