What is the inverse of f(x)=x^2+10x,x>=-5 ?

The inverse of f(x)=x^2+10x,x>=-5 is -5+sqrt(x+25),-sqrt(x+25)-5

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inverse of f(x)=x^2+10x,x>=-5

inverse

f (x) = x^{2} + 10 x, x \geq - 5

- 5 + x + 25, - x + 25 - 5

Solution steps

y = x^{2} + 10 x

Replace

x

with

y

x = y^{2} + 10 y

Solve for

y, x = y^{2} + 10 y

- 5 + x + 25, - x + 25 - 5

f (x) = \frac{ln ( \frac{x}{3 - x} )}{4}

f (x) = 3 x^{2} + x

lo g_{10} (0.016576)

f (x) = 24 + 9 x

f (x) = (x - 9)^{2}, (9, \infty)

What is the inverse of f(x)=x^2+10x,x>=-5 ?
The inverse of f(x)=x^2+10x,x>=-5 is -5+sqrt(x+25),-sqrt(x+25)-5