What is the inverse of f(x)=14x^3-5 ?

The inverse of f(x)=14x^3-5 is cube root of (x+5)/(14)

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inverse of f(x)=14x^3-5

inverse

f (x) = 14 x^{3} - 5

3 \frac{x + 5}{14}

Solution steps

y = 14 x^{3} - 5

Replace

x

with

y

x = 14 y^{3} - 5

Solve for

y, x = 14 y^{3} - 5

3 \frac{x + 5}{14}

f (x) = 7 x + 24

\frac{x ^{2}}{- x ^{2} + 4}

f (x) = 1 + lo g_{\frac{1}{e}} (2 - x)

f (x) = x 3 + 3 x 2 + 1

f (x) = \frac{( 7 x + 3 )}{( x - 5 )}

What is the inverse of f(x)=14x^3-5 ?
The inverse of f(x)=14x^3-5 is cube root of (x+5)/(14)