What is the inverse of y=3x^2+6x+15 ?

The inverse of y=3x^2+6x+15 is (-6+sqrt(12x-144))/6 ,(-6-sqrt(12x-144))/6

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inverse of y=3x^2+6x+15

inverse

y = 3 x^{2} + 6 x + 15

\frac{- 6 + 12 x - 144}{6}, \frac{- 6 - 12 x - 144}{6}

Solution steps

y = 3 x^{2} + 6 x + 15

Replace

x

with

y

x = 3 y^{2} + 6 y + 15

Solve for

y, x = 3 y^{2} + 6 y + 15

\frac{- 6 + 12 x - 144}{6}, \frac{- 6 - 12 x - 144}{6}

\frac{1 + 2 \cdot z ^{- 2}}{1 + \frac{1}{2 \cdot z ^{- 2}}}

\frac{x - 4}{2 x + 1}

f (x) = - 0.7 x + 35

f (x) = 3 2 x - 2

f (x) = 8 + 3 x - 9

What is the inverse of y=3x^2+6x+15 ?
The inverse of y=3x^2+6x+15 is (-6+sqrt(12x-144))/6 ,(-6-sqrt(12x-144))/6