What is the inverse of (5-s)/((s+3)(s-1)) ?

The inverse of (5-s)/((s+3)(s-1)) is (-2s-1+sqrt(16s^2+24s+1))/(2s),(-2s-1-sqrt(16s^2+24s+1))/(2s)

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inverse of (5-s)/((s+3)(s-1))

inverse

\frac{5 - s}{( s + 3 ) ( s - 1 )}

\frac{- 2 s - 1 + 16 s ^{2} + 24 s + 1}{2 s}, \frac{- 2 s - 1 - 16 s ^{2} + 24 s + 1}{2 s}

Solution steps

y = \frac{5 - s}{( s + 3 ) ( s - 1 )}

Replace

s

with

y

s = \frac{5 - y}{( y + 3 ) ( y - 1 )}

Solve for

y, s = \frac{5 - y}{( y + 3 ) ( y - 1 )}

\frac{- 2 s - 1 + 16 s ^{2} + 24 s + 1}{2 s}, \frac{- 2 s - 1 - 16 s ^{2} + 24 s + 1}{2 s}

\frac{x ^{3}}{x ^{3} + 5}

y^{- 1} = e^{\frac{x + 4}{3}} - 2

f (x) = \frac{( x ^{2} )}{( x + 1 )}

\frac{x - 4}{x ^{2} + 8 x + 16}

f (x) = \frac{7}{4 x + 5}

What is the inverse of (5-s)/((s+3)(s-1)) ?
The inverse of (5-s)/((s+3)(s-1)) is (-2s-1+sqrt(16s^2+24s+1))/(2s),(-2s-1-sqrt(16s^2+24s+1))/(2s)