What is the inverse of f(x)=-((sqrt(x)+17))/3 ?

The inverse of f(x)=-((sqrt(x)+17))/3 is 289+102x+9x^2

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inverse of f(x)=-((sqrt(x)+17))/3

inverse

f (x) = - \frac{( x + 17 )}{3}

289 + 102 x + 9 x^{2}

Solution steps

y = - \frac{x + 17}{3}

Replace

x

with

y

x = - \frac{y + 17}{3}

Solve for

y, x = - \frac{y + 17}{3}

289 + 102 x + 9 x^{2}

f (x) = (x - 4)^{2} - 8

f (x) = \frac{7 x - 9}{6 x + 5}

\frac{lo g _{5} ( 3 ^{(x)} + 9 )}{( 2 )}

\frac{( - lo g _{2} ( x ) + 5 )}{8}

f (x) = 5 - lo g_{2} (x + 1)

What is the inverse of f(x)=-((sqrt(x)+17))/3 ?
The inverse of f(x)=-((sqrt(x)+17))/3 is 289+102x+9x^2