What is the inverse of y= 3/4 sqrt(2/3)x-4/9 ?

The inverse of y= 3/4 sqrt(2/3)x-4/9 is (2sqrt(6)(9x+4))/(27)

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inverse of y= 3/4 sqrt(2/3)x-4/9

inverse

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

\frac{2 6 ( 9 x + 4 )}{27}

Solution steps

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

Replace

x

with

y

x = \frac{3}{4} \frac{2}{3} y - \frac{4}{9}

Solve for

y, x = \frac{3}{4} \frac{2}{3} y - \frac{4}{9}

\frac{2 6 ( 9 x + 4 )}{27}

f (x) = \frac{x ^{2}}{x + 1}

\frac{( x + 2 )}{x - 2}

g (x) = (x + 1)^{2}

f (x) = \frac{x ^{2}}{x + 2}

f (x) = 4^{0.02 x}

What is the inverse of y= 3/4 sqrt(2/3)x-4/9 ?
The inverse of y= 3/4 sqrt(2/3)x-4/9 is (2sqrt(6)(9x+4))/(27)