What is the inverse of f(x)=n(n+1) ?

The inverse of f(x)=n(n+1) is (-1+sqrt(1+4n))/2 ,(-1-sqrt(1+4n))/2

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inverse of f(x)=n(n+1)

inverse

f (x) = n (n + 1)

\frac{- 1 + 1 + 4 n}{2}, \frac{- 1 - 1 + 4 n}{2}

Solution steps

y = n (n + 1)

Replace

n

with

y

n = y (y + 1)

Solve for

y, n = y (y + 1)

\frac{- 1 + 1 + 4 n}{2}, \frac{- 1 - 1 + 4 n}{2}

f (x) = - 6 (x - 3)^{2} - 2

f (x) = \frac{3 x - 2}{x - 5}

f (x) = 4 \cdot lo g_{\frac{1}{2}} (- x + 10)

f (x) = \frac{x ^{2} - 1}{x ^{2} - 9}

f (x) = Y (x) (x)^{1} = \frac{x - 4}{2} + 3

What is the inverse of f(x)=n(n+1) ?
The inverse of f(x)=n(n+1) is (-1+sqrt(1+4n))/2 ,(-1-sqrt(1+4n))/2