What is the inverse of 3/2 x^2+9/2 x ?

The inverse of 3/2 x^2+9/2 x is (-9+sqrt(81+24x))/6 ,(-9-sqrt(81+24x))/6

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inverse of 3/2 x^2+9/2 x

inverse

\frac{3}{2} x^{2} + \frac{9}{2} x

\frac{- 9 + 81 + 24 x}{6}, \frac{- 9 - 81 + 24 x}{6}

Solution steps

y = \frac{3}{2} x^{2} + \frac{9}{2} x

Replace

x

with

y

x = \frac{3}{2} y^{2} + \frac{9}{2} y

Solve for

y, x = \frac{3}{2} y^{2} + \frac{9}{2} y

\frac{- 9 + 81 + 24 x}{6}, \frac{- 9 - 81 + 24 x}{6}

f (y) = 3 x^{2} + x

f (x) = (\frac{4}{( x - 4 ) ^{2}})

f (x) = ln (x + 1) - 4

f (x) = \frac{5 x - 11}{10}

\frac{- 2 s - 8}{s ^{2} + 4 s + 4}

What is the inverse of 3/2 x^2+9/2 x ?
The inverse of 3/2 x^2+9/2 x is (-9+sqrt(81+24x))/6 ,(-9-sqrt(81+24x))/6