What is the inverse of f(x)=((3x+1)^2)/2-4 ?

The inverse of f(x)=((3x+1)^2)/2-4 is (sqrt(2x+8)-1)/3 ,(-sqrt(2x+8)-1)/3

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inverse of f(x)=((3x+1)^2)/2-4

inverse

f (x) = \frac{( 3 x + 1 ) ^{2}}{2} - 4

\frac{2 x + 8 - 1}{3}, \frac{- 2 x + 8 - 1}{3}

Solution steps

y = \frac{( 3 x + 1 ) ^{2}}{2} - 4

Replace

x

with

y

x = \frac{( 3 y + 1 ) ^{2}}{2} - 4

Solve for

y, x = \frac{( 3 y + 1 ) ^{2}}{2} - 4

\frac{2 x + 8 - 1}{3}, \frac{- 2 x + 8 - 1}{3}

y = 7 x^{2} - 55

y = \frac{( x ^{2} )}{8}, (x > 0)

f (x) = \frac{( 2 x - 3 ) + 3}{2}

375 + 0.1 q

\frac{1}{s + 1} - \frac{1}{s + 2}

What is the inverse of f(x)=((3x+1)^2)/2-4 ?
The inverse of f(x)=((3x+1)^2)/2-4 is (sqrt(2x+8)-1)/3 ,(-sqrt(2x+8)-1)/3