What is the inverse of (x-1)/(x^2+3x+2) ?

The inverse of (x-1)/(x^2+3x+2) is (-3x+1+sqrt(x^2-10x+1))/(2x),(-3x+1-sqrt(x^2-10x+1))/(2x)

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inverse of (x-1)/(x^2+3x+2)

inverse

\frac{x - 1}{x ^{2} + 3 x + 2}

\frac{- 3 x + 1 + x ^{2} - 10 x + 1}{2 x}, \frac{- 3 x + 1 - x ^{2} - 10 x + 1}{2 x}

Solution steps

y = \frac{x - 1}{x ^{2} + 3 x + 2}

Replace

x

with

y

x = \frac{y - 1}{y ^{2} + 3 y + 2}

Solve for

y, x = \frac{y - 1}{y ^{2} + 3 y + 2}

\frac{- 3 x + 1 + x ^{2} - 10 x + 1}{2 x}, \frac{- 3 x + 1 - x ^{2} - 10 x + 1}{2 x}

f (x) = \frac{e ^{x}}{1 + 7 e ^{x}}

f (x) = 3 (x - 1)^{2} - 5

f (x) = x^{2} - 4 x + 17

f (x) = 0.25 x

f (x) = \frac{2 x - 3}{x + 3}

What is the inverse of (x-1)/(x^2+3x+2) ?
The inverse of (x-1)/(x^2+3x+2) is (-3x+1+sqrt(x^2-10x+1))/(2x),(-3x+1-sqrt(x^2-10x+1))/(2x)