What is the inverse of f(x)=(x*200)/((x+200)+1) ?

The inverse of f(x)=(x*200)/((x+200)+1) is -(201x)/(x-200)

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inverse of f(x)=(x*200)/((x+200)+1)

inverse

f (x) = \frac{x \cdot 200}{( x + 200 ) + 1}

- \frac{201 x}{x - 200}

Solution steps

y = \frac{x \cdot 200}{x + 200 + 1}

Replace

x

with

y

x = \frac{y \cdot 200}{y + 200 + 1}

Solve for

y, x = \frac{y \cdot 200}{y + 200 + 1}

- \frac{201 x}{x - 200}

f (x) = \frac{( - 2 x - 8 )}{5}

\frac{4 x}{26 x - 10}

f (x) = - x^{2} + 4 x - 4

lo g_{\frac{1}{2}} (16 (\frac{1}{2})^{x}) + 2^{3}

What is the inverse of f(x)=(x*200)/((x+200)+1) ?
The inverse of f(x)=(x*200)/((x+200)+1) is -(201x)/(x-200)