What is the inverse of f(x)=\sqrt[3]{x-2}+3 ?

The inverse of f(x)=\sqrt[3]{x-2}+3 is x^3-9x^2+27x-25

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inverse of f(x)=\sqrt[3]{x-2}+3

inverse

x^{3} - 9 x^{2} + 27 x - 25

Solution steps

Replace

x

with

y

Solve for

x^{3} - 9 x^{2} + 27 x - 25

f (x) = \frac{( - 2 x - 8 )}{5}

\frac{4 x}{26 x - 10}

f (x) = - x^{2} + 4 x - 4

lo g_{\frac{1}{2}} (16 (\frac{1}{2})^{x}) + 2^{3}

y = sin^{2} (x)

What is the inverse of f(x)=\sqrt[3]{x-2}+3 ?
The inverse of f(x)=\sqrt[3]{x-2}+3 is x^3-9x^2+27x-25