What is the inverse of f(x)=((sqrt(7x-1))/2)/(2) ?

The inverse of f(x)=((sqrt(7x-1))/2)/(2) is (16x^2+1)/7

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inverse of f(x)=((sqrt(7x-1))/2)/(2)

inverse

f (x) = \frac{\frac{7 x - 1}{2}}{2}

\frac{16 x ^{2} + 1}{7}

Solution steps

y = \frac{\frac{7 x - 1}{2}}{2}

Replace

x

with

y

x = \frac{\frac{7 y - 1}{2}}{2}

Solve for

y, x = \frac{\frac{7 y - 1}{2}}{2}

\frac{16 x ^{2} + 1}{7}

f (x) = \frac{5 x + 3}{5 x - 4}

f (x) = - \frac{12}{lo g _{2} ( a )}

f (x) = 2 - x + 1 - 2 x

3 (0.5 x - 2)^{2} - 2

f (x) = x^{2} - 2 x + 8

What is the inverse of f(x)=((sqrt(7x-1))/2)/(2) ?
The inverse of f(x)=((sqrt(7x-1))/2)/(2) is (16x^2+1)/7