What is the inverse of 3(0.5x-2)^2-2 ?

The inverse of 3(0.5x-2)^2-2 is 2(sqrt((x+2)/3)+2),2(-sqrt((x+2)/3)+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 3(0.5x-2)^2-2

inverse

3 (0.5 x - 2)^{2} - 2

2 (\frac{x + 2}{3} + 2), 2 (- \frac{x + 2}{3} + 2)

Solution steps

y = 3 (0.5 x - 2)^{2} - 2

Replace

x

with

y

x = 3 (0.5 y - 2)^{2} - 2

Solve for

y, x = 3 (0.5 y - 2)^{2} - 2

2 (\frac{x + 2}{3} + 2), 2 (- \frac{x + 2}{3} + 2)

f (x) = x^{2} - 2 x + 8

f (x) = 5 x^{2} - 3 x - 5

f (x) = (\frac{( 7 x )}{( 8 x - 1 )})

f (x) = 2 y - 5

f (x) = y^{2} - 2 y

What is the inverse of 3(0.5x-2)^2-2 ?
The inverse of 3(0.5x-2)^2-2 is 2(sqrt((x+2)/3)+2),2(-sqrt((x+2)/3)+2)