What is the inverse of f(x)=x^2-2x+8 ?

The inverse of f(x)=x^2-2x+8 is 1+sqrt(x-7),1-sqrt(x-7)

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inverse of f(x)=x^2-2x+8

inverse

f (x) = x^{2} - 2 x + 8

1 + x - 7, 1 - x - 7

Solution steps

y = x^{2} - 2 x + 8

Replace

x

with

y

x = y^{2} - 2 y + 8

Solve for

y, x = y^{2} - 2 y + 8

1 + x - 7, 1 - x - 7

f (x) = 5 x^{2} - 3 x - 5

f (x) = (\frac{( 7 x )}{( 8 x - 1 )})

f (x) = 2 y - 5

f (x) = y^{2} - 2 y

\frac{3 x}{4 x - 1}

What is the inverse of f(x)=x^2-2x+8 ?
The inverse of f(x)=x^2-2x+8 is 1+sqrt(x-7),1-sqrt(x-7)