What is the inverse of g(x)=(-x-2)/(x+4) ?

The inverse of g(x)=(-x-2)/(x+4) is (-2-4x)/(x+1)

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inverse of g(x)=(-x-2)/(x+4)

inverse

g (x) = \frac{- x - 2}{x + 4}

\frac{- 2 - 4 x}{x + 1}

Solution steps

y = \frac{- x - 2}{x + 4}

Replace

x

with

y

x = \frac{- y - 2}{y + 4}

Solve for

y, x = \frac{- y - 2}{y + 4}

\frac{- 2 - 4 x}{x + 1}

f (x) = \frac{x + 5}{x + 9}

f (x) = \frac{10 x + 7}{7 x - 4}

f (x) = - \frac{2}{3} x - 4

(- 1, 8), (4, - 2)

2 csc (\frac{1}{3} (x - 1)) - 2

What is the inverse of g(x)=(-x-2)/(x+4) ?
The inverse of g(x)=(-x-2)/(x+4) is (-2-4x)/(x+1)