What is the inverse of 1/((s-4)(s-6)) ?

The inverse of 1/((s-4)(s-6)) is (5s+sqrt(s(s+1)))/s ,(5s-sqrt(s(s+1)))/s

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 1/((s-4)(s-6))

inverse

\frac{1}{( s - 4 ) ( s - 6 )}

\frac{5 s + s ( s + 1 )}{s}, \frac{5 s - s ( s + 1 )}{s}

Solution steps

y = \frac{1}{( s - 4 ) ( s - 6 )}

Replace

s

with

y

s = \frac{1}{( y - 4 ) ( y - 6 )}

Solve for

y, s = \frac{1}{( y - 4 ) ( y - 6 )}

\frac{5 s + s ( s + 1 )}{s}, \frac{5 s - s ( s + 1 )}{s}

a^{4} + a^{2} - 1

f (x) = ln (x + 3) + 1

y = \frac{3}{( x + 4 ) ^{\frac{1}{3}}} - 5

f (x) = r (3) = - 5 x 3 - 7 x 2 - 10 x - 5

f (x) = - 5^{2} + 3 t + 3

What is the inverse of 1/((s-4)(s-6)) ?
The inverse of 1/((s-4)(s-6)) is (5s+sqrt(s(s+1)))/s ,(5s-sqrt(s(s+1)))/s