What is the inverse of y= 3/((x+4)^{1/3)}-5 ?

The inverse of y= 3/((x+4)^{1/3)}-5 is (27)/(x^3+15x^2+75x+125)-4

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inverse of y= 3/((x+4)^{1/3)}-5

inverse

y = \frac{3}{( x + 4 ) ^{\frac{1}{3}}} - 5

\frac{27}{x ^{3} + 15 x ^{2} + 75 x + 125} - 4

Solution steps

y = \frac{3}{( x + 4 ) ^{\frac{1}{3}}} - 5

Replace

x

with

y

x = \frac{3}{( y + 4 ) ^{\frac{1}{3}}} - 5

Solve for

y, x = \frac{3}{( y + 4 ) ^{\frac{1}{3}}} - 5

\frac{27}{x ^{3} + 15 x ^{2} + 75 x + 125} - 4

f (x) = r (3) = - 5 x 3 - 7 x 2 - 10 x - 5

f (x) = - 5^{2} + 3 t + 3

f (x) = 4 - 1 - x^{2}

49 + 2.3 (h - 61)

What is the inverse of y= 3/((x+4)^{1/3)}-5 ?
The inverse of y= 3/((x+4)^{1/3)}-5 is (27)/(x^3+15x^2+75x+125)-4