What is the inverse of f(x)=sqrt((4x+40)/3) ?

The inverse of f(x)=sqrt((4x+40)/3) is (3x^2-40)/4

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inverse of f(x)=sqrt((4x+40)/3)

inverse

f (x) = \frac{4 x + 40}{3}

\frac{3 x ^{2} - 40}{4}

Solution steps

y = \frac{4 x + 40}{3}

Replace

x

with

y

x = \frac{4 y + 40}{3}

Solve for

y, x = \frac{4 y + 40}{3}

\frac{3 x ^{2} - 40}{4}

f (x) = y - 5

6 e^{x - 4}

\frac{t ^{3}}{3}

f (x) = f (x) = \frac{2}{5} x^{3} - 4

f (x) = (\frac{1}{0.15 x + 1})

What is the inverse of f(x)=sqrt((4x+40)/3) ?
The inverse of f(x)=sqrt((4x+40)/3) is (3x^2-40)/4