What is the inverse of y=4sqrt(x-3)+5 ?

The inverse of y=4sqrt(x-3)+5 is (x^2+25}{16}-\frac{5x)/8+3

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inverse of y=4sqrt(x-3)+5

inverse

y = 4 x - 3 + 5

\frac{x ^{2} + 25}{16} - \frac{5 x}{8} + 3

Solution steps

y = 4 x - 3 + 5

Replace

x

with

y

x = 4 y - 3 + 5

Solve for

y, x = 4 y - 3 + 5

\frac{x ^{2} + 25}{16} - \frac{5 x}{8} + 3

\frac{( z - 8 ) ^{2}}{z ^{2} - 64}

g (x) = \frac{4 x}{7 x - 5}

f (x) = 3 + 4 x - 3

4 - 6 (4 - 1)

f (x) = 2 sin (x) - 7

What is the inverse of y=4sqrt(x-3)+5 ?
The inverse of y=4sqrt(x-3)+5 is (x^2+25}{16}-\frac{5x)/8+3