What is the inverse of arcsec(x) 2/(sqrt(3)) ?

The inverse of arcsec(x) 2/(sqrt(3)) is sec((sqrt(3)x)/2)

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inverse of arcsec(x) 2/(sqrt(3))

inverse

arcsec (x) \frac{2}{3}

sec (\frac{3 x}{2})

Solution steps

Solve for

arcsec (x), y = arcsec (x) \frac{2}{3}

arcsec (x) = \frac{3 y}{2}

arcsec (a) = b \Rightarrow a = sec (b)

sec (\frac{3 y}{2})

Substitute

y = x

sec (\frac{3 x}{2})

\frac{- 3 x - 11}{2 x - 8}

f (x) = 2 x^{7} + 7

f (x) = - 5 (- 5 x - 9)^{2} - 6, x \geq - 95

f (x) = 1 + 2 (1 - \frac{2}{x + 1})

cos (3 x + 2 π) + 3

What is the inverse of arcsec(x) 2/(sqrt(3)) ?
The inverse of arcsec(x) 2/(sqrt(3)) is sec((sqrt(3)x)/2)