What is the inverse of f(x)=-1+log_{3}(x-1) ?

The inverse of f(x)=-1+log_{3}(x-1) is 3^{x+1}+1

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inverse of f(x)=-1+log_{3}(x-1)

inverse

f (x) = - 1 + lo g_{3} (x - 1)

3^{x + 1} + 1

Solution steps

y = - 1 + lo g_{3} (x - 1)

Replace

x

with

y

x = - 1 + lo g_{3} (y - 1)

Solve for

y, x = - 1 + lo g_{3} (y - 1)

3^{x + 1} + 1

f (x) = (x + 4)^{2} - 3, x \geq - 4

x^{2} - 16, x \geq 0

4

1 - 3 x + 1 - 5 x

\frac{x ^{2} - 8}{x - 3}

What is the inverse of f(x)=-1+log_{3}(x-1) ?
The inverse of f(x)=-1+log_{3}(x-1) is 3^{x+1}+1