What is the inverse of f(x)=(x-1)^2+9 ?

The inverse of f(x)=(x-1)^2+9 is sqrt(x-9)+1,-sqrt(x-9)+1

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inverse of f(x)=(x-1)^2+9

inverse

f (x) = (x - 1)^{2} + 9

x - 9 + 1, - x - 9 + 1

Solution steps

y = (x - 1)^{2} + 9

Replace

x

with

y

x = (y - 1)^{2} + 9

Solve for

y, x = (y - 1)^{2} + 9

x - 9 + 1, - x - 9 + 1

f (x) = 4 x + 1 + 2

f (x) = \frac{( 5 x - 7 )}{9 x + 2}

f (x) = (x - 1)^{2} + 6

\frac{( z - 1 )}{( z - e ^{- 1} )}

What is the inverse of f(x)=(x-1)^2+9 ?
The inverse of f(x)=(x-1)^2+9 is sqrt(x-9)+1,-sqrt(x-9)+1