What is the inverse of (2x^2+20x+68)/(x^2+10x+16) ?

The inverse of (2x^2+20x+68)/(x^2+10x+16) is (-5x+10+3sqrt(x^2-4))/(x-2),(-5x+10-3sqrt(x^2-4))/(x-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (2x^2+20x+68)/(x^2+10x+16)

inverse

\frac{2 x ^{2} + 20 x + 68}{x ^{2} + 10 x + 16}

\frac{- 5 x + 10 + 3 x ^{2} - 4}{x - 2}, \frac{- 5 x + 10 - 3 x ^{2} - 4}{x - 2}

Solution steps

y = \frac{2 x ^{2} + 20 x + 68}{x ^{2} + 10 x + 16}

Replace

x

with

y

x = \frac{2 y ^{2} + 20 y + 68}{y ^{2} + 10 y + 16}

Solve for

y, x = \frac{2 y ^{2} + 20 y + 68}{y ^{2} + 10 y + 16}

\frac{- 5 x + 10 + 3 x ^{2} - 4}{x - 2}, \frac{- 5 x + 10 - 3 x ^{2} - 4}{x - 2}

cosh (- 1 x)

y = \frac{64}{25} x^{2}

f (x) = 0.5 x^{0.5}

f (x) = 5 x - 11 = - 36

f (x) = 18 - x^{2}

What is the inverse of (2x^2+20x+68)/(x^2+10x+16) ?
The inverse of (2x^2+20x+68)/(x^2+10x+16) is (-5x+10+3sqrt(x^2-4))/(x-2),(-5x+10-3sqrt(x^2-4))/(x-2)