What is the inverse of f(x)= 3/(5x^2) ?

The inverse of f(x)= 3/(5x^2) is sqrt(3/(5x)),-sqrt(3/(5x))

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inverse of f(x)= 3/(5x^2)

inverse

f (x) = \frac{3}{5 x ^{2}}

\frac{3}{5 x}, - \frac{3}{5 x}

Solution steps

y = \frac{3}{5 x ^{2}}

Replace

x

with

y

x = \frac{3}{5 y ^{2}}

Solve for

y, x = \frac{3}{5 y ^{2}}

\frac{3}{5 x}, - \frac{3}{5 x}

- \frac{1}{2} tan (2 π x)

f (x) = \frac{( x - 7 )}{( x + 4 )}

6 + 5 x - 5

f (x) = - \frac{1}{2} lo g_{5} (\frac{1}{x + 3})

\frac{10}{( t + 16 ) ( t + 25 )}

What is the inverse of f(x)= 3/(5x^2) ?
The inverse of f(x)= 3/(5x^2) is sqrt(3/(5x)),-sqrt(3/(5x))