What is the inverse of f(x)=\sqrt[3]{z-1}+4 ?

The inverse of f(x)=\sqrt[3]{z-1}+4 is z^3-12z^2+48z-63

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inverse of f(x)=\sqrt[3]{z-1}+4

inverse

z^{3} - 12 z^{2} + 48 z - 63

Solution steps

Replace

z

with

x

Solve for

z^{3} - 12 z^{2} + 48 z - 63

f (x) = 3 ln (5 x - 2 + 6)

y = - 4 - 2 x + 1 - 2

g (x) = \frac{x}{5} + 2

f (x) = - 0.1 x^{2} + 90

f (x) = - \frac{1}{2} (\frac{1}{2})^{x} + 7

What is the inverse of f(x)=\sqrt[3]{z-1}+4 ?
The inverse of f(x)=\sqrt[3]{z-1}+4 is z^3-12z^2+48z-63