What is the domain of f(x)= 1/(3x^2-33x+54) ?

The domain of f(x)= 1/(3x^2-33x+54) is x 9

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domain of f(x)= 1/(3x^2-33x+54)

domain

f (x) = \frac{1}{3 x ^{2} - 33 x + 54}

x < 2 or 2 < x < 9 or x > 9

Interval Notation

(- \infty, 2) \cup (2, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = 2

The function domain

x < 2 or 2 < x < 9 or x > 9

f (x) = lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6

\frac{9 x - 4}{4 x + 8}

y = \frac{x ^{3}}{- x ^{2} + 4}

f (x) = lo g_{4} (5 x - 9)

\frac{x + 2}{x ^{2} - 9}

What is the domain of f(x)= 1/(3x^2-33x+54) ?
The domain of f(x)= 1/(3x^2-33x+54) is x<2\lor 2<x<9\lor x>9