What is the domain of-log_{2}(3(x-2))+4 ?

The domain of-log_{2}(3(x-2))+4 is x>2

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domain of-log_{2}(3(x-2))+4

domain

- lo g_{2} (3 (x - 2)) + 4

x > 2

Interval Notation

(2, \infty)

Solution steps

Find positive values for logs:

x > 2

The function domain

x > 2

f (x) = \frac{8 x ^{2} - 10 x - 3}{2 x ^{2} - 9 x + 9}

f (x) = \frac{( x ^{2} + 3 )}{x + 3}

y = - 2 x - 7

f (x) = (x - 1) (x + 2)

y = x - 5 - 1

What is the domain of-log_{2}(3(x-2))+4 ?
The domain of-log_{2}(3(x-2))+4 is x>2