What is the domain of f(x)= x/(sqrt(x^2-5)) ?

The domain of f(x)= x/(sqrt(x^2-5)) is x sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= x/(sqrt(x^2-5))

domain

f (x) = \frac{x}{x ^{2} - 5}

x < - 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

x < - 5 or x > 5

f (x) = - 2 x^{2} + 12 x + 5

f (x) = \frac{5}{x ^{2} - x}

f (x) = - 3 t

f (x) = lo g_{2} (x - 3) + 1

f (x) = f (x) = \frac{( x ^{2} + 16 )}{( x ^{2} - 9 )}

What is the domain of f(x)= x/(sqrt(x^2-5)) ?
The domain of f(x)= x/(sqrt(x^2-5)) is x<-sqrt(5)\lor x>sqrt(5)