What is the domain of f(x)=2sqrt(-x^2+10x) ?

The domain of f(x)=2sqrt(-x^2+10x) is 0<= x<= 10

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domain of f(x)=2sqrt(-x^2+10x)

domain

f (x) = 2 - x^{2} + 10 x

0 \leq x \leq 10

Interval Notation

[0, 10]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 10

The function domain

0 \leq x \leq 10

f (x) = 2^{x + 1} - 8

g (x) = lo g_{10} (16 x - x^{2})

F (x) = \frac{( 8 x + 5 )}{( 4 x + 2 )}

f (x) = \frac{( x + 7 ) ^{2}}{6 x - 2}

y = \frac{1}{x + 7} - 20

What is the domain of f(x)=2sqrt(-x^2+10x) ?
The domain of f(x)=2sqrt(-x^2+10x) is 0<= x<= 10