What is the domain of g(x)=log_{10}(16x-x^2) ?

The domain of g(x)=log_{10}(16x-x^2) is 0<x<16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of g(x)=log_{10}(16x-x^2)

domain

g (x) = lo g_{10} (16 x - x^{2})

0 < x < 16

Interval Notation

(0, 16)

Solution steps

Find positive values for logs:

0 < x < 16

The function domain

0 < x < 16

F (x) = \frac{( 8 x + 5 )}{( 4 x + 2 )}

f (x) = \frac{( x + 7 ) ^{2}}{6 x - 2}

y = \frac{1}{x + 7} - 20

f (x) = x - x^{2}

y = \frac{- 2}{x - 5}

What is the domain of g(x)=log_{10}(16x-x^2) ?
The domain of g(x)=log_{10}(16x-x^2) is 0<x<16