What is the domain of f(x)=((x+7)^2)/(sqrt(6x-2)) ?

The domain of f(x)=((x+7)^2)/(sqrt(6x-2)) is x> 1/3

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domain of f(x)=((x+7)^2)/(sqrt(6x-2))

domain

f (x) = \frac{( x + 7 ) ^{2}}{6 x - 2}

x > \frac{1}{3}

Interval Notation

(\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

Find undefined (singularity) points:

x = \frac{1}{3}

Combine real regions and undefined points for final function domain

x > \frac{1}{3}

y = \frac{1}{x + 7} - 20

f (x) = x - x^{2}

y = \frac{- 2}{x - 5}

f (x) = \frac{x}{2 x - [ x ]}

x^{2} - x - 6

What is the domain of f(x)=((x+7)^2)/(sqrt(6x-2)) ?
The domain of f(x)=((x+7)^2)/(sqrt(6x-2)) is x> 1/3