What is the domain of f(x)= 1/(sqrt(2+x)) ?

The domain of f(x)= 1/(sqrt(2+x)) is x>-2

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domain of f(x)= 1/(sqrt(2+x))

domain

f (x) = \frac{1}{2 + x}

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

g (x) = \frac{x + 4}{x ^{2} - 9}

y = x^{2} - 4 x - 5

y = 2 x^{2} - 8 x + 8

5 \cdot (\frac{1}{4})^{x}

f (x) = \frac{x - 3}{3 x + 2}

What is the domain of f(x)= 1/(sqrt(2+x)) ?
The domain of f(x)= 1/(sqrt(2+x)) is x>-2