What is the domain of g(x)= 1/(x-3)+6 ?

The domain of g(x)= 1/(x-3)+6 is x 3

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domain of g(x)= 1/(x-3)+6

domain

g (x) = \frac{1}{x - 3} + 6

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = x^{2} (x + 1)^{3} (x - 3)

f (x) = \frac{x}{x ^{2} - 5 x - 14}

f (x) = \frac{1}{x ^{2} - 16}

f (x) = \frac{x + 3}{x ^{2} - 36}

What is the domain of g(x)= 1/(x-3)+6 ?
The domain of g(x)= 1/(x-3)+6 is x<3\lor x>3