What is the domain of f(x)=(\sqrt[3]{x})^2 ?

The domain of f(x)=(\sqrt[3]{x})^2 is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(\sqrt[3]{x})^2

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{6}{x - 7}

\frac{x + 19}{x - 17}

f (x) = \frac{( 1 + x - 1 )}{x}

f (x) = \frac{π}{2} - arcsin (2 x)

f (x) = 2 sin (x) + cos (2 x)

What is the domain of f(x)=(\sqrt[3]{x})^2 ?
The domain of f(x)=(\sqrt[3]{x})^2 is -infinity <x<infinity