What is the domain of f(x)=((sqrt(1+x)-1))/x ?

The domain of f(x)=((sqrt(1+x)-1))/x is -1 0

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domain of f(x)=((sqrt(1+x)-1))/x

domain

f (x) = \frac{( 1 + x - 1 )}{x}

- 1 \leq x < 0 or x > 0

Interval Notation

[- 1, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or x > 0

f (x) = \frac{π}{2} - arcsin (2 x)

f (x) = 2 sin (x) + cos (2 x)

f (x) = x \cdot 4 - x^{2}

f (x) = \frac{x + 3}{ln ( x - 1 )}

\frac{4}{x + 1}

What is the domain of f(x)=((sqrt(1+x)-1))/x ?
The domain of f(x)=((sqrt(1+x)-1))/x is -1<= x<0\lor x>0