What is the domain of y=(x-1)/(x^2) ?

The domain of y=(x-1)/(x^2) is x 0

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domain of y=(x-1)/(x^2)

domain

y = \frac{x - 1}{x ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

x^{2} y - x^{2} - 4 y = 0

\frac{4 x - 12}{( x - 2 ) ^{2}}

\frac{x}{- 2 x + 9}

f (x) = \frac{x}{12 - x - x ^{2}}

What is the domain of y=(x-1)/(x^2) ?
The domain of y=(x-1)/(x^2) is x<0\lor x>0