What is the domain of f(x)= x/(12-x-x^2) ?

The domain of f(x)= x/(12-x-x^2) is x 3

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domain of f(x)= x/(12-x-x^2)

domain

f (x) = \frac{x}{12 - x - x ^{2}}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4, x = 3

The function domain

x < - 4 or - 4 < x < 3 or x > 3

f (x) = 3 - ∣ x - 2 ∣

f (x) = \frac{x ^{2} + x - 2}{x ^{2} + 3 x + 2}

\frac{x - 2 + ∣ x - 1 ∣}{∣ x - 2 ∣ + x - 1}

f (x) = cos (arccos (x))

f (x) = \frac{8}{( x - 4 ) ^{2}}

What is the domain of f(x)= x/(12-x-x^2) ?
The domain of f(x)= x/(12-x-x^2) is x<-4\lor-4<x<3\lor x>3