What is the domain of f(x)=\sqrt[3]{6x^2-x^3} ?

The domain of f(x)=\sqrt[3]{6x^2-x^3} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{6x^2-x^3}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x}{12 - x - x ^{2}}

f (x) = 3 - ∣ x - 2 ∣

f (x) = \frac{x ^{2} + x - 2}{x ^{2} + 3 x + 2}

\frac{x - 2 + ∣ x - 1 ∣}{∣ x - 2 ∣ + x - 1}

f (x) = cos (arccos (x))

What is the domain of f(x)=\sqrt[3]{6x^2-x^3} ?
The domain of f(x)=\sqrt[3]{6x^2-x^3} is -infinity <x<infinity