What is the domain of f(x)=sqrt(x+6-x^2) ?

The domain of f(x)=sqrt(x+6-x^2) is -2<= x<= 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x+6-x^2)

domain

f (x) = x + 6 - x^{2}

- 2 \leq x \leq 3

Interval Notation

[- 2, 3]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 3

The function domain

- 2 \leq x \leq 3

f (x) = \frac{3 x}{( x - 2 ) ( x + 4 )}

\frac{3 x + 1}{4}

- 4 x + 4

f (x) = \frac{2 - x}{x ^{4} - 1}

f (x) = 4 - x^{2} - 4 x

What is the domain of f(x)=sqrt(x+6-x^2) ?
The domain of f(x)=sqrt(x+6-x^2) is -2<= x<= 3