What is the domain of f(x)=\sqrt[10]{x-1} ?

The domain of f(x)=\sqrt[10]{x-1} is x>= 1

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domain of f(x)=\sqrt[10]{x-1}

domain

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

y = \frac{x ^{2} + x - 12}{x ^{2} - 4}

h (x) = \frac{x + 5}{x ^{2} - 9}

y = 4 + \frac{5}{1 + x - 3}

y = \frac{2}{x + 3}

f (x) = 5 (x^{2} - 20)

What is the domain of f(x)=\sqrt[10]{x-1} ?
The domain of f(x)=\sqrt[10]{x-1} is x>= 1