What is the domain of f(x)=(sqrt(1-5x))/(x^2+4) ?

The domain of f(x)=(sqrt(1-5x))/(x^2+4) is x<= 1/5

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domain of f(x)=(sqrt(1-5x))/(x^2+4)

domain

f (x) = \frac{1 - 5 x}{x ^{2} + 4}

x \leq \frac{1}{5}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{5}

The function domain

x \leq \frac{1}{5}

4 + ln (x)

lo g_{\frac{1}{3}} (\frac{x ^{2} - x - 6}{2}) + x + 1

f (x) = x + 9

f (x) = \frac{2 x ^{2}}{x ^{2} - 6 x - 7}

f (x) = (ln (x))

What is the domain of f(x)=(sqrt(1-5x))/(x^2+4) ?
The domain of f(x)=(sqrt(1-5x))/(x^2+4) is x<= 1/5