What is the domain of f(x)=(x^2+9)/(x+3) ?

The domain of f(x)=(x^2+9)/(x+3) is x -3

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domain of f(x)=(x^2+9)/(x+3)

domain

f (x) = \frac{x ^{2} + 9}{x + 3}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

\frac{x ^{2} - 4}{x ^{2} - 9}

g (z) = - z^{2} - 4 z + 7

\frac{x}{x + 10} + x^{2} + 6 x - 7

f (x) = (\frac{x}{4 - x ^{2}})

2 x - 5

What is the domain of f(x)=(x^2+9)/(x+3) ?
The domain of f(x)=(x^2+9)/(x+3) is x<-3\lor x>-3