What is the domain of y=sqrt(x-4/x) ?

The domain of y=sqrt(x-4/x) is -2 = 2

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domain of y=sqrt(x-4/x)

domain

y = x - \frac{4}{x}

- 2 \leq x < 0 or x \geq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

- 2 \leq x < 0 or x \geq 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 2 \leq x < 0 or x \geq 2

f (x) = \frac{x}{x ^{2} + 16}

\frac{2 x ^{2} + 3 x - 5}{x ^{2} + 2}

h (x) = 3 3 x + 1

f (x) = 3 x^{- 2}

g (x) = 3^{x} + 3

What is the domain of y=sqrt(x-4/x) ?
The domain of y=sqrt(x-4/x) is -2<= x<0\lor x>= 2